Loading…
Loading…
Tender ID
Eligibility, documents, scope and key termsEligibility, required documents, scope of work and key terms of this tender, in one click.
| # | Company | Amount | Rank | Status |
|---|---|---|---|---|
| 1 | L1₹2.0 LAccepted-AOC MOONIDIH DHANBAD 828129 | DHANBAD | DHANBAD | JHARKHAND | 828129 | L1 | Accepted-AOC L1 | |
| 2 | L2₹1.7 L+₹1,658.16 (0.98%)Rejected-AOC MOONIDIH COLLIERY CIL | L2 | Rejected-AOC L2 | |
| 3 | L3₹1.7 L+₹1,989.79 (1.18%)Rejected-AOC COAL INDIA LIMITED | L3 | Rejected-AOC L3 |
Tender Value
₹1.7 L
EMD Value
₹2,073
Closing Date
2 Mar 2026, 5:00 pmClosed
Eligibility, documents, scope and key termsEligibility, required documents, scope of work and key terms of this tender, in one click.
S.K.Panja
Office of the Project Officer,WJ Area
Construction of 1 no toilet in belt dip of LHD section near 500MH main line in UG in XVI seam at Moonidih Colliery W.J Area .
2026_BCCL_353647_1
BCCL/WJA/MND/SUR/2025-26/98
Open Tender
Miscellaneous Works
Percentage
7 days
Moonidih Colliery, WJ Area
Please refer to NIT.
11 documents required · 11 mandatory
₹2,073
23 Mar 2026
19 Feb 2026
3 Mar 2026
19 Feb 2026
2 Mar 2026
19 Feb 2026
Construction of 1 no toilet in belt dip of LHD section near 500MH main line in UG in XVI seam at Moonidih Colliery W.J Area .
Removal of scrap materials in belt dip of LHD section near 500MH main line for making space for toilet : 15 unskilled main shift.
Ddebris cleaning from belt dip of LHD section near 500MH main line for making space for toilet : 12m x 4.8m xvavg ht 0.7mt=40.32m3 For 4m³ debris cleaning, 3 unskilled manshift is required cost /m³ = 3*1367.6/4=Rs.1025.70/m³
Drilling-blasting in floor stone for making tank of toilet =1.2mx1.2mx1.0m=1.44m³ For 10m³ =3skilled (for drillng/blasting)+ 10 unskilled manshift(for mucking) required. Cost /m³=[(3x1436.60)+(10x1367.60)]/10=Rs2390.28/m3
dimention of toilet L= 2.5m w= 2.25m Recess cutting in floor: length (2.5+0.10+0.10) X 0.50m width X 0.30m htX 2 side= 0.81m³ length 2.25 + (2.25-.76) = 3.74x.50 width x 0.30ht= 0.56m³ total recess = 0.81+ 0.56= 1.37m³ analysis For 2 m3=3unskilled manshift is required . cost/m³= 3x1367.60/2= Rs.2051.40/m³
Brick flat soling FPS bricks CD-50 bricks in foundation & plinth:2.25x2.0=4.50m2
3' pcc on floor=2.25x2.0x0.08=0.36m³
Brick work (1:4)with FPS bricks CD-50 bricks in Floor 7 plinth level : For wall=(2.5+2.5+2.25+1.49)x0.25x(1.5+0.3)=8.74X.25X 1.80= 3.93m³
Brick work (1:4)with FPS bricks CD-50 bricks in super structure plinth level up to V-level in all shape & size : (a) volune of door area ht 1.50m to 2.30 width=0.76m vol= 0.76x0.80x0.25=0.15m³ (b) volume of above 1.50m =(2.5+2.5+2.25+2.25)x0.23x(2.3-1.5)=9.50 x0 .25x 0.80= 1.90m³ therefor net volume (excluding door0 =( b-a)= 1.90-0.15=1.75m³
Providing & fixing PAN(comode) including flushing cistern: 1no
12 mm cement plastering (1:6)= (a) outer side =( 2.5+0.25+2.25+0.25+2.5+0.25+2.25+0.25)x2.30 =10.50x 2.30= 24.15m² (b) innier side (2+2.25+2+2.25) x2.3= 8.50x2.30= 19.55m² © less door area 2 times = 1.7x0.76x 2times= 1.29m² (d) area of perimeter of door wall face = (1.7 + 0.76+ 1.70+0.76)x 0.25= 1.23m² = net area = a+b-c+d= 24.15+19.55-1.29+1.23=43.64m² (2.5+2.5+2.25+1.5)x2.30)x2side=35.65m2
Providing two extra lead including loading,unloading, stacking and carrying of 1000 Bricks,(1 at surface + 1 in UG). carriage of brick,extra 1 number lead @ 436.90/1000, cost of 2 lead = (2x 436.90)/1000= 873.8/1000bricks=0.87/briks number of brick=3.93+1.75=5.68m³, @ 494bricks/m³,number of bricks=2805.92+ 326.37=3132.29=say 3133
Providing two extra leadfor loading,unloading, stacking and carrying of sand,(1 at surface + 1 in UG) . carriage of sand,extra 1 number lead @ Rs234.05/m³, cost of 2 lead = (2x 234.05)/m³= 468.1/m³ Sand For B/W=(3.93+1.75) m³x 0.26=4.39m³ Sand for plastering= 35.65 m²x0.015=0.53m3 sand for flooring = 0.15/10X5.06=0.80m³ Total= 5.44 + 1.89m³= 7.33m³
Providing two extra lead forloading,unloading, stacking and carrying of cement, (1 at surface + 1 in UG). carriage of cement ,extra 1 number lead @ Rs135.55/te , cost of 2extra lead = (2x 135.55)/te= 271.10/te Cement For B/W=5.68m³x1.9=10.79bags cement for plaster=(35.65m²x7.5)/100=2.67 bags Total = 10.79+ 2.67 = 13.46 bags say 14 bags x50/1000= 0.70 te
Add CP 15% as per clause 4.17.1 of Civil Eng. Manual & BCCL SOR
Total impact of GST for the purpose of CTC
stage.html
html • 0.04 MB
tech_eval.pdf
boq_comp_chart.xlsx
xlsx
fin_eval.pdf
aoc.pdf
Tap a document below to read it instantly. You can also download everything as a ZIP if you prefer.
details.html
html • 0.04 MB
Tendernotice_1.pdf
PDF • 2.64 MB
BOQ_366458.xls
BOQ • 0.34 MB
Download all tender documents and submit your bid
Disclaimer: TenderKart has made every reasonable effort to ensure that the information on this page is accurate and authentic, however it cannot be held liable for any third-party claims or losses or any damages. TenderKart makes no warranty, expressed or implied, as to the results obtained from the use of this information. If you notice any error or omission, please let us know at .